document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1144604>Question 1144604</A>: <I><SPAN STYLE=\"word-break: break-all;\"> linear functions given h(4)=-10 and h(-1)=10 then find h(3)<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #765774 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=765774\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "A non-algebraic solution, using logical reasoning and an understanding of what it means for a function to be linear....<br><BR>\n" );
document.write( "(1) 3 is one-fifth of the way from 4 to -1 (look at the three numbers on a number line...)<br><BR>\n" );
document.write( "(2) Therefore -- since the function is linear -- h(3) is one-fifth of the way from h(4) to h(-1).<br><BR>\n" );
document.write( "From h(4) to h(-1) is a change of 20, from -10 to +10.<BR>\n" );
document.write( "One-fifth of 20 is 4; the change from h(4) to h(3) is 4.<br><BR>\n" );
document.write( "ANSWER: h(3) = h(4)+4 = -10 +4 = -6 </SPAN>\n" );
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