document.write( "Question 1144517: Prince Christopher and Princess Dagney were 63 miles apart at dawn. Prince Christopher
\n" ); document.write( "began the journey to the meeting place at 7 a.m. at 3 mph. Three hours later Princess Dagney set
\n" ); document.write( "out to meet him. If they met at 4 p.m., how fast did the princess travel?
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Algebra.Com's Answer #765672 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "The algebraic solution from the other tutor is fine, and it is a good example of how basic algebra can be used to solve problems like this.

\n" ); document.write( "If an algebraic solution is not required, logical analysis can solve the problem easily. And the logical reasoning is good exercise for your brain....

\n" ); document.write( "The prince traveled for 9 hours at 3mph; the distance he traveled was 9*3 = 27 miles.

\n" ); document.write( "The total distance to be traveled was 63 miles; so the distance the princess traveled was 63-27 = 36 miles.

\n" ); document.write( "Since the princess started 3 hours after the prince, she traveled for 6 hours.

\n" ); document.write( "Since she traveled 36 miles in 6 hours, her speed was 36/6 = 6mph.
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