document.write( "Question 1144517: Prince Christopher and Princess Dagney were 63 miles apart at dawn. Prince Christopher
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document.write( "began the journey to the meeting place at 7 a.m. at 3 mph. Three hours later Princess Dagney set
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document.write( "out to meet him. If they met at 4 p.m., how fast did the princess travel? \n" );
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Algebra.Com's Answer #765651 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Prince Christopher and Princess Dagney were 63 miles apart at dawn. \n" ); document.write( " Prince Christopher began the journey to the meeting place at 7 a.m. at 3 mph. \n" ); document.write( " Three hours later Princess Dagney set out to meet him. \n" ); document.write( " If they met at 4 p.m., how fast did the princess travel? : \n" ); document.write( ": \n" ); document.write( "if the met a 4 PM, 6 hr = travel time of the princess and 9 hrs = travel time of the prince \n" ); document.write( "let s = the speed of the princess \n" ); document.write( ": \n" ); document.write( "Write a distance equation; dist = speed * time \n" ); document.write( "6s + 3(9) = 63 \n" ); document.write( "6s = 63 - 27 \n" ); document.write( "6s = 36 \n" ); document.write( "s = 36/6 \n" ); document.write( "s = 6 mph is the speed of the princess \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |