document.write( "Question 15419: If twice a certian number is increased by 3, the result is 8 less than threes time a number. Find the number \n" ); document.write( "
Algebra.Com's Answer #7656 by elima(1433)\"\" \"About 
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First of all lets make x=the number;
\n" ); document.write( "Now we know twice that number increased(+) by 3;
\n" ); document.write( "2x+3;
\n" ); document.write( "The result is(=);
\n" ); document.write( "8 lease(-) than 3 times that number;
\n" ); document.write( "3x-8;
\n" ); document.write( "So we have;
\n" ); document.write( "2x+3=3x-8
\n" ); document.write( "Subtract 3 from both sides;
\n" ); document.write( "2x+3-3=3x-8-3
\n" ); document.write( "2x=3x-11
\n" ); document.write( "Now subtract 3x from both sides;
\n" ); document.write( "2x-3x=3x-11-3x;
\n" ); document.write( "-x=-11
\n" ); document.write( "We do not want to leave the answer with -x so we will divide each side by -1;
\n" ); document.write( "x=11
\n" ); document.write( "Hope you understand
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