document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1144442>Question 1144442</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A 31​% dextrous solution ​(31 mg per 100 mL of​ solution) is given intravenously. Suppose a total of 1.038 L of the solution is given over a 6​-hour period. <BR>\n" );
document.write( "a. What is the flow rate in units of​ mL/hr?<BR>\n" );
document.write( "b. If each mL contains 13 drops​ (the drop factor is expressed as 13 ​gtt/mL), what is the flow rate in units of​ gtt/hr?<BR>\n" );
document.write( "c. During the 6​-hour ​period, how much dextrous is​ delivered? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #765571 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52864)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=765571\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .\r<BR>\n" );
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document.write( "&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;In your post, &nbsp;replace &nbsp;\"dextrous\" &nbsp;by &nbsp;\"dextrose\" &nbsp;at &nbsp;EVERY OCCURRENCE &nbsp;<U>to avoid nonsense</U> &nbsp;(!)\r<BR>\n" );
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document.write( "(a)  To find flow rate, divide the given volume by the given time:\r\n" );
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document.write( "         floe rate = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.038%2F6 ALIGN=MIDDLE  ALT=\"1.038%2F6\"   DISABLED_style= \"max-width:90%; height:auto;\" > liter per hour (L/h).     (1)\r\n" );
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document.write( "     Then convert it into mL per hour.  The base for conversion is  1 Liter = 1000 mL.\r\n" );
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document.write( "(b)  To find flow rate in drops per hour, take your value from (a) of milliliters per hour and multiply it by the factor 13.\r\n" );
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document.write( "(c)  OBVIOUSLY,  the answer is 0.31*1.038 kilograms = 0.31*1038 grams.\r\n" );
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document.write( "I am in fear.\r<BR>\n" );
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document.write( "The problem goes with the terms related to medicine,\r<BR>\n" );
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document.write( "but the author is absolutely unfamiliar with special terminology in the area &nbsp;(?) &nbsp;(!)\r<BR>\n" );
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document.write( "Who are you, &nbsp;the author ?\r<BR>\n" );
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