document.write( "Question 1144423: jacky was riding her new bike on the playground with other children.everyone was riding a bicycle or A tricycle.if jacky counted 12 WHEELS NOT INCLUDING HER OWN. HOW MANY KIDS WERE ON THE PLAYGROUND \n" ); document.write( "

Algebra.Com's Answer #765535 by ikleyn(52851) $\"\"$ $\"About$

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document.write( "Let \"b\" be the number of bicycles and \"t\" be the number of tricycles, NOT COUNTING Jacky's bike.\r\n" );
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document.write( "Then from the condition, you have this equation\r\n" );
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document.write( "    2b + 3t = 12,      (1)      (counting wheels).\r\n" );
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document.write( "Thus you have one equation for 2 unknowns.\r\n" );
document.write( "But you have, in addition, a restriction that the solution must be in INTEGER NON-NEGATIVE numbers.\r\n" );
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document.write( "It is very serious restriction, and in your case it provides a unique solution.\r\n" );
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document.write( "With this restriction, equation (1) has these and only these soLutions\r\n" );
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document.write( "    a      b\r\n" );
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document.write( "    0       4\r\n" );
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document.write( "    3       2\r\n" );
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document.write( "    6       0\r\n" );
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document.write( "Now, from the condition, it is NATURALLY to assume that  a > 0  and  b > 0.\r\n" );
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document.write( "Then you have ONLY ONE solution  a= 3,  b= 2.\r\n" );
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document.write( "So, there are 3 bicycles and 2 tricycles, not counting Jacky's bike.\r\n" );
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document.write( "In this way, you get the ANSWER :\r\n" );
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document.write( "    there are 3 + 2 = 5 children on the playground, non counting Jacky herself.\r\n" );
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document.write( "    Or 5+1 = 6, counting Jacky.\r\n" );
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document.write( "The problem is solved.\r\n" );
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