document.write( "Question 1144413: Given that the area of a rhombus is 40cm² and that each side has a length of 15cm, find the angles of the Rhombus \n" ); document.write( "
Algebra.Com's Answer #765519 by ikleyn(52781)\"\" \"About 
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document.write( "For each parallelogram, its area is the product of the lengths of any two its adjacent sides\r\n" );
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document.write( "by the sine of the angle between them\r\n" );
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document.write( "    Area = \"a%2Ab%2Asin%28alpha%29\".\r\n" );
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document.write( "For a rhombus, this formula takes the form\r\n" );
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document.write( "    Area = \"a%5E2%2Asin%28alpha%29\",\r\n" );
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document.write( "where \"a\" is the length of any side and \"alpha\" is any of the four angles of the rhombus.\r\n" );
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document.write( "Thus in our case\r\n" );
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document.write( "    40 = \"15%5E2%2Asin%28alpha%29\",   \"sin%28alpha%29\" = \"40%2F225\" = \"8%2F45\",\r\n" );
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document.write( "and an acute angle of the rhombus is\r\n" );
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document.write( "    \"alpha\" = \"arcsin%288%2F45%29\" = arcsin(0.17778) = 0.17873 radians = 10.25 degrees (approximately).    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "See the lesson\r
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