document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1144404>Question 1144404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Walt made an extra $9000 last year from a part-time job. He invested part of the money at 5% and the rest at 6%. He made a total of $480 in interest. How much was invested at 6%?<BR>\n" );
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document.write( "(1) A traditional algebraic solution....<br><BR>\n" );
document.write( "let x be the amount invested at 5%<BR>\n" );
document.write( "then 9000-x is the amount invested at 6%<br><BR>\n" );
document.write( "The total interest is 5% of x plus 6% of (9000-x):<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=.05%28x%29%2B.06%289000-x%29+=+480 ALIGN=MIDDLE  ALT=\".05%28x%29%2B.06%289000-x%29+=+480\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "Solve using basic algebra....<br><BR>\n" );
document.write( "(2) A solution found by comparing the actual interest to the amounts of interest if the whole $9000 had been invested at one rate of the other....<br><BR>\n" );
document.write( "$9000 all at 5% would yield $450 interest<BR>\n" );
document.write( "$9000 all at 6% would yield $540 interest<br><BR>\n" );
document.write( "$480 is 1/3 of the way from $450 to $540 (picture the three numbers 450, 480, and 540 on a number line...)<br><BR>\n" );
document.write( "Therefore, 1/3 of the total was invested at the higher rate.<br><BR>\n" );
document.write( "ANSWER: 1/3 of $9000, or $3000, at 6%; the other $6000 at 5%.<br><BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( ".05(6000)+.06(3000) = 300+180 = 480 </SPAN>\n" );
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