document.write( "Question 1144390: In a random selected family of three biologically theirs, normally conceived children, find the probability that this family has:
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Algebra.Com's Answer #765489 by ikleyn(52787)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "            Assuming that the probability to have in a family a boy  (B)  or a girl  (G)  is   \"1%2F2\"\r
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document.write( "(A)  The probability that all 3 children are of the same gender =     \r\n" );
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document.write( "         = The probability of  \"%281%2F2%29%2A%281%2F2%29%2A%281%2F2%29\" = \"1%2F8\"  to have 3 girls \r\n" );
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document.write( "     PLUS\r\n" );
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document.write( "           the probability of  \"%281%2F2%29%2A%281%2F2%29%2A%281%2F2%29\" = \"1%2F8\"  to have 3 boys =\r\n" );
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document.write( "     = \"1%2F8\" + \"1%2F8\" = \"2%2F8\" = \"1%2F4\".    ANSWER\r\n" );
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document.write( "(B)  P = P(BBG) + P(BGB) + P(GBB) + P(GGB) + P(GBG) + P(GGB) = \"6%2F8\" = \"3%2F4\".     ANSWER\r\n" );
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document.write( "Notice that the probability of the n.B  is the complement to the probability of the n.A, as it should be.\r\n" );
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document.write( "It is an additional argument/check that the solution is correct.\r\n" );
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