document.write( "Question 105194: Hello Tutor, \r
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document.write( "I am in need of some help if you can help me out I would appreciate it. \r
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document.write( "Solve by completing the square: \r
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document.write( "1.) 4x^2 + x - 3 = 0 I got -3/4 , 1 is this correct? \r
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document.write( "2.) x^2 = 5x + 2 I think this is 5 +- sqrt of 33 / 2 is this correct? \r
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document.write( "3.) 4x^2 + 2x - 3 = 0 I got -1+- sqrt of 13 / 8 is this correct? \r
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document.write( "I am not sure I am solving these questions of completing the squares correctly if you could tell me if I have them correct I would appreciate it. Thanks in advance. \n" );
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Algebra.Com's Answer #76547 by edjones(8007)![]() ![]() You can put this solution on YOUR website! 4x^2+x-3=0 \n" ); document.write( "x^2+x/4-3/4=0 divide both sides by 4. \n" ); document.write( "x^2+x/4 =3/4 \n" ); document.write( "x^2+x/4+1/64=3/4+1/64 divide the 2nd term coefficient by 2 and square it and add it to both sides. \n" ); document.write( "(x+1/8)^2=49/64 factor \n" ); document.write( "x+1/8=+-7/8 square root of each side. \n" ); document.write( "x=-1/8+-7/8 \n" ); document.write( "x=3/4, x=-1 \n" ); document.write( "you shouldn't have any problem doing the other 2. \n" ); document.write( "Ed \n" ); document.write( " |