document.write( "Question 1144270: 5y/6+3y/4=19/12 find the value of y \n" ); document.write( "

Algebra.Com's Answer #765339 by addingup(3677) $\"\"$ $\"About$

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5y/6+3y/4=19/12 find the value of y:
\n" ); document.write( "3y*(1/4)+5y*6^-1 = 19/12
\n" ); document.write( "3/4y+5y*6^-1 = 19/12
\n" ); document.write( "3/4y+5y*(1/6) = 19/12
\n" ); document.write( "3/4y+5/6y = 19/12
\n" ); document.write( "19/12y= 19/12
\n" ); document.write( "y = (19/12)/(19/12)
\n" ); document.write( "y = 1
\n" ); document.write( " \n" ); document.write( "

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