document.write( "Question 105148: An airplane flew 4 hours with a 25 mph tail wind. The return trip against the same wind took 5 hours. Find the speed of the airplane in still air. \n" ); document.write( "
Algebra.Com's Answer #76528 by ankor@dixie-net.com(22740)\"\" \"About 
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An airplane flew 4 hours with a 25 mph tail wind. The return trip against the same wind took 5 hours. Find the speed of the airplane in still air.
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\n" ); document.write( "Let s = speed in still air
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\n" ); document.write( "(s+25) = speed with wind
\n" ); document.write( "(s-25) = speed against the wind
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\n" ); document.write( "The trip out and the trip back are equal distance. Write a distance equation.
\n" ); document.write( "Distance = time * speed
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\n" ); document.write( "5(s-25) = 4(s+25)
\n" ); document.write( "5s - 125 = 4s + 100
\n" ); document.write( "5s - 4s = 100 + 125
\n" ); document.write( "s = 225 mph in still air
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\n" ); document.write( "Check the solution by finding the distances to be equal:
\n" ); document.write( "Against: 5(200) = 1000 mi
\n" ); document.write( "With: 4(250) = 1000 mi confirms our solution
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