document.write( "Question 1144239: David Is 6 years older than his sister Delia. In 10 years the sum of There age 52. how old are David and Delia
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Algebra.Com's Answer #765275 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Something like this, if you want/need to use formal algebra....

\n" ); document.write( "L = Delia now
\n" ); document.write( "L+6 = David now

\n" ); document.write( "L+10 + Delia 10 years from now
\n" ); document.write( "L+16 = David 10 years from now

\n" ); document.write( "(L+10)+(L+16) = 52

\n" ); document.write( "Solve using basic algebra.

\n" ); document.write( "Or informally....

\n" ); document.write( "Sum of their ages 10 years from now is 52.
\n" ); document.write( "So sum of their ages now is 52-20 = 32.
\n" ); document.write( "Subtract 6 years from David's age to make them the same age; the sum of their ages is now 32-6 = 26.
\n" ); document.write( "Then Delia's age is 26/2 = 13.
\n" ); document.write( "Add the 6 years back on to David's age to find out he is 13+6 = 19.
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