document.write( "Question 1144195: David is two years older than peter and five years older than John.Their ages add up to 44. How old is John? \n" ); document.write( "
Algebra.Com's Answer #765225 by Theo(13342)\"\" \"About 
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let d = david's age.
\n" ); document.write( "let p = peter's age.
\n" ); document.write( "let j = john's age.\r
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\n" ); document.write( "\n" ); document.write( "david is 2 years older than peter, therefore d = p + 2.
\n" ); document.write( "david is 5 years older than john, therefore d = j + 5.\r
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\n" ); document.write( "\n" ); document.write( "you are given that d + p + j = 44\r
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\n" ); document.write( "\n" ); document.write( "in d = p + 2, solve for p to get:
\n" ); document.write( "p = d - 2.\r
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\n" ); document.write( "\n" ); document.write( "in d = j + 5, solve for j to get:
\n" ); document.write( "j = d - 5.\r
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\n" ); document.write( "\n" ); document.write( "replace p and j with their equivalent values in d to get:
\n" ); document.write( "d + p + j = 44 becomes:
\n" ); document.write( "d + (d - 2) + (d - 5) = 44
\n" ); document.write( "combine like terms to get:
\n" ); document.write( "3 * d - 7 = 44
\n" ); document.write( "add 7 to both sides of the equation to get 3 * d = 51
\n" ); document.write( "solve for d to get d = 51 / 3 = 17.\r
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\n" ); document.write( "\n" ); document.write( "since d = p + 2, then p = 15.
\n" ); document.write( "since d = j + 5, then j = 12.\r
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\n" ); document.write( "\n" ); document.write( "d + p + j becomes 17 + 15 + 12 = 44\r
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\n" ); document.write( "\n" ); document.write( "the values for d and p and j are confirmed to be good.\r
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\n" ); document.write( "\n" ); document.write( "the solution is that john is 12 years old.\r
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