document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1144116>Question 1144116</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if a certain no. is added to the numerator and the denominator of 7/9, the result is 5/6. find the number. (use 1 variable thanks) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #765113 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=765113\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x be the number.<BR>\n" );
document.write( "(7 + x) / (9 + x) = 5 / 6<BR>\n" );
document.write( "cross multiply to get (7 + x) * 6 = (9 + x) * 5.<BR>\n" );
document.write( "simplify to get 42 + 6x = 45 + 5x.<BR>\n" );
document.write( "subtract 5x from both sides of that tand subtract 42 from both sides of that equation to get x = 3<BR>\n" );
document.write( "that's your solution.<BR>\n" );
document.write( "(7 + 3) / (9 + 3) = 10 / 12<BR>\n" );
document.write( "multiply numerator and denominator of 10 / 12 by (1/2) / (1/2) to get 5 / 6.<BR>\n" );
document.write( "solution is confirmed to be good.<BR>\n" );
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