document.write( "Question 105132: Find the sum of the series
\n" ); document.write( "1x2 + 2x2^2 + 3x2^3 +...+ 100x2^100\r
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Algebra.Com's Answer #76501 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
\"S+=1%2A2%2B2%2A2%5E2%2B3.2%5E2\"\"....\"\"100%2A2%5E100\"\r
\n" ); document.write( "\n" ); document.write( "\"2S+=+1%2A2%5E2%2B2%2A2%5E3%2B......\"\"%2B99%2A2%5E100+%2B+100%2A2%5E+101\"\r
\n" ); document.write( "\n" ); document.write( "Subtracting these two, we get:\r
\n" ); document.write( "\n" ); document.write( "\"S\" - \"2S\" = \"-S\"\r
\n" ); document.write( "\n" ); document.write( "\"-S+=+2%2B2%5E2%2B2%5E3\"\"...........\"\"100%2A2%5E101\"\r
\n" ); document.write( "\n" ); document.write( "\"S=100%2A2%5E101-2%282%5E100-1%29%2F%282-1%29\"\r
\n" ); document.write( "\n" ); document.write( "= \"100%2A2%5E101-2%5E101%2B2\"\r
\n" ); document.write( "\n" ); document.write( "= \"99%2A2%5E101%2B2\"\r
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