document.write( "Question 1144011: Find the equation of the hyperbola with the following properties.\r
\n" ); document.write( "\n" ); document.write( " Foci at (5,-4) and (13,-4)
\n" ); document.write( " Vertices at (6,-4) and (12,-4)
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Algebra.Com's Answer #764996 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "(1) Foci at (5,-4) and (13,-4)

\n" ); document.write( "So...

\n" ); document.write( "Transverse axis is horizontal, so branches open right and left.
\n" ); document.write( "The general equation is \"%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1\".
\n" ); document.write( "The center (h,k) is halfway between the foci, at (9,-4).
\n" ); document.write( "c=4.

\n" ); document.write( "(2) Vertices at (6,-4) and (12,-4)

\n" ); document.write( "So the length of the transverse axis is 6, which means a=3.

\n" ); document.write( "Use c^2=a^c+b^2 to determine a^2; then write the equation.
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