document.write( "Question 98545This question is from textbook Calculus with Applications Brief Version
\n" ); document.write( ": I'm having trouble solving for 'x' in this equation \"log4%28x-2%29%2B+log4%28x%2B6%29=2\". I have tried re-arranging it to make an exponential equation, but I end up confusing myself even more. \r
\n" ); document.write( "\n" ); document.write( "Thank you for looking at this.
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Algebra.Com's Answer #76487 by bimanewton(8)\"\" \"About 
You can put this solution on YOUR website!
\"log4%28x-2%29%2B+log4%28x%2B6%29=2\"\r
\n" ); document.write( "\n" ); document.write( "\"log%284x-8%29%2A%284x%2B24%29=log100\"
\n" ); document.write( "\"16%28x%5E%282%29%29%2B64x-192=100\"\r
\n" ); document.write( "\n" ); document.write( "\"16%28x%5E%282%29%29%2B64x-292=0\"\r
\n" ); document.write( "\n" ); document.write( "x1=\"%28-64%2Bsquareroot%284096%2B18688%29%29%2F%2832%29\"
\n" ); document.write( " =\"2.7\"
\n" ); document.write( "x2=\"%28-64-squareroot%284096%2B18688%29%29%2F%2832%29\"
\n" ); document.write( " =\"-6.7\"
\n" ); document.write( "
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