document.write( "Question 1143922: When K is divided by 4, the remainder is 1. What is the remainder when (3k-1) is divided by 4?
\n" ); document.write( "A)0
\n" ); document.write( "B)1
\n" ); document.write( "C)2
\n" ); document.write( "F)4
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Algebra.Com's Answer #764851 by Theo(13342)\"\" \"About 
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k / 4 = x + 1/4, where x is an integer and the remainder is 1.
\n" ); document.write( "solve for k to get k = 4x + 1
\n" ); document.write( "when x = 0, k = 1
\n" ); document.write( "when x = 1, k = 5
\n" ); document.write( "when x = 2, k = 9
\n" ); document.write( "when k = 1, you get 1/4 = 0 + 1/4
\n" ); document.write( "when k = 5, you get 5/4 = 1 + 1/4
\n" ); document.write( "when k = 9, you get 9/4 = 2 + 1/4
\n" ); document.write( "the value of k can be 1, 5, 9, 13, 17, ....
\n" ); document.write( "we'll assume k = 17
\n" ); document.write( "k/4 = 17/4 = 4 + 1/4
\n" ); document.write( "the remainder is always 1.
\n" ); document.write( "when k 17, (3k-1)/4 becomes 50/4 = 12 + 2/4
\n" ); document.write( "when k = 9, (3k-1)/4 becomes 26/4 = 6 + 2/4
\n" ); document.write( "when k = 5, (3k-1)/4 becomes 14/4 = = 3 + 2/4
\n" ); document.write( "the remainder is always 2.
\n" ); document.write( "that's your solution.
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