document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=14643>Question 14643</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i have a problem, The word Problem is as follows \"I have three times as many dime as quarters. If the coins are worth $6.60, how many quaters are there?\"     I came up with the equation 3x*.10+x*.25=6.60 and i simplified it to 3x*.10+.25x=6.60 but I do not know what to do after that. Thank You for your time and help                                      </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #7648 by </B><A HREF=/tutors/aboutme.mpl?userid=LilSkittleMd><B>LilSkittleMd(119)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=LilSkittleMd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=7648\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two equations are<BR>\n" );
document.write( "d=3q<BR>\n" );
document.write( "0.25q+0.10d=6.60<BR>\n" );
document.write( "Substitute the value of d into the second equation<BR>\n" );
document.write( "0.25q+0.10(3q)=6.60<BR>\n" );
document.write( "0.25q+0.3q=6.60<BR>\n" );
document.write( ".55q=6.60<BR>\n" );
document.write( "q=12<BR>\n" );
document.write( "Plug in the value of q into one of the original equations<BR>\n" );
document.write( "d=3(12)<BR>\n" );
document.write( "d=36<BR>\n" );
document.write( "There are 12 quarters and 36 dimes </SPAN>\n" );
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