document.write( "Question 1143812: find the vertex of the parabola whose equation is y²+3x-2y+7=0 \n" ); document.write( "
Algebra.Com's Answer #764725 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "With vertex (h,k), the vertex form of the equation is

\n" ); document.write( "\"%28x-h%29+=+%281%2F%284p%29%29%28y-k%29%5E2\"

\n" ); document.write( "Put the equation in that form by completing the square in y and then solving for x.

\n" ); document.write( "\"y%5E2%2B3x-2y%2B7+=+0\" given
\n" ); document.write( "\"y%5E2-2y+=+-3x-7\" isolate the y terms
\n" ); document.write( "\"y%5E2-2y%2B1+=+-3x-7%2B1+=+-3x-6\" complete the square in y
\n" ); document.write( "\"%28y-1%29%5E2+=+-3%28x%2B2%29\" put in vertex form
\n" ); document.write( "\"x%2B2+=+%28-1%2F3%29%28y-1%29%5E2\" done....

\n" ); document.write( "The vertex is (h,k) = (-2,1).
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