document.write( "Question 1143792: find the equation of the circle woth center at (-3,8) and tangent to the line
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Algebra.Com's Answer #764695 by ikleyn(52803)\"\" \"About 
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document.write( "As soon as you find the radius of the circle, you will be in position to write its equation.\r\n" );
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document.write( "The radius of the circle is equal to the distance from the given center to the given line.\r\n" );
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document.write( "To find this distance, use the general formula for the distance from the point (p,q) to the line Ax + By + C = 0\r\n" );
document.write( "in the coordinate plane\r\n" );
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document.write( "    d = \"abs%28Ap%2BBq%2BC%29%2Fsqrt%28A%5E2%2BB%5E2%29\".      (1)\r\n" );
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document.write( "In your case  A= 1, B= -1, C= 5, p= -3, q= 8.\r\n" );
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document.write( "So from the formula (1), the distance from the point (-3,8) to the line x-y+5 = 0 is\r\n" );
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document.write( "    d = \"abs%281%2A%28-3%29+-+1%2A8+%2B+5%29%2Fsqrt%281%5E2+%2B+%28-1%29%5E2%29\" = \"6%2Fsqrt%282%29\".\r\n" );
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document.write( "Thus the radius of the circle is  r = d = \"6%2Fsqrt%282%29\".\r\n" );
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document.write( "Then the standard equation of the circle is\r\n" );
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document.write( "    \"%28x-%28-3%29%29%5E2\" + \"%28y-8%29\" = \"%286%2Fsqrt%282%29%29%5E2\",\r\n" );
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document.write( "or, equivalently,\r\n" );
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document.write( "    \"%28x%2B3%29%5E2\" + \"%28y-8%29%5E2\" = 18.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Regarding the basic formula (1),  see the lessons\r
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