document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1143754>Question 1143754</A>: <I><SPAN STYLE=\"word-break: break-all;\"> you invested ​$29000 in two accounts paying 6 % and 8 % annual​ interest, respectively.<BR>\n" );
document.write( "If the total interest earned for the year was $ 2040 comma how much was invested at each​ rate?  </SPAN>\n" );
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document.write( "Here is a non-algebraic method for solving this kind of problem, treating it as a mixture problem.<br><BR>\n" );
document.write( "$29000 all invested at 6% would yield $1740 interest; all invested at 8% would yield $2320 interest.<br><BR>\n" );
document.write( "The way the money is split between the two investments is exactly determined by where the actual amount of interest lies between  those two amounts.<br><BR>\n" );
document.write( "So consider the three interest amounts on a number line: 1740, 2040, and 2320.<br><BR>\n" );
document.write( "(1) The difference between $1740 and $2320 is $580; the difference between $1740 and $2040 is $300.<BR>\n" );
document.write( "(2) So we can say that the actual amount of interest is 300/580 = 30/58 = 15/29 of the way from $1740 to $2320.<BR>\n" );
document.write( "(3) That means 15/29 of the total was invested at the higher rate.<br><BR>\n" );
document.write( "ANSWER: (15/29) of $29,000, or $15,000 at 8%; the rest, $14,000, at 6%.<br><BR>\n" );
document.write( "CHECK: .08(15000)+.06(14000) = 1200+840 = 2040 </SPAN>\n" );
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