document.write( "Question 105103This question is from textbook Precalculus
\n" ); document.write( ": A rectangle garden is 10ft longer than it is wide. Its area is 875 ft squared. What are its dimensions? \n" ); document.write( "
Algebra.Com's Answer #76461 by kmcruz09(38)\"\" \"About 
You can put this solution on YOUR website!
First, let as assume.
\n" ); document.write( "Let x = the width of the plot
\n" ); document.write( "x + 10 = length of the plot\r
\n" ); document.write( "\n" ); document.write( "Then the area is x(x + 10)
\n" ); document.write( "Since it is stated in the problem that the area is 875 square feet, our final equation will be:
\n" ); document.write( "\"x+%28x+%2B+10%29+=+875\"
\n" ); document.write( "Solve it:
\n" ); document.write( "\"x+%28x+%2B+10%29+=+875\"
\n" ); document.write( "\"x%5E2+%2B+10x+=+875\"
\n" ); document.write( "\"x%5E2+%2B+10x+%2B+-875+=+0\"
\n" ); document.write( "Applying the quadratic formula
\n" ); document.write( "\"x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+\"
\n" ); document.write( "\"x+=+%28-%2810%29+%2B-+sqrt%28+10%5E2-4%2A1%2A%28-875%29%29%29%2F%282%2A1%29\"
\n" ); document.write( "\"x+=+%28-10+%2B-+sqrt%28+100-%28-3500%29%29%29%2F2\"
\n" ); document.write( "\"x+=+%28-10+%2B-+sqrt%283600%29%29%2F2\"
\n" ); document.write( "\"x+=+%28-10+%2B-+60%29%2F2\"\r
\n" ); document.write( "\n" ); document.write( "Now we can solve for the two roots
\n" ); document.write( "\"x+=+%28-10+%2B+60%29%2F2\" or \"x+=+%28-10+-+60%29%2F2\"
\n" ); document.write( "\"x+=+%2850%29%2F2\" or \"x+=+%28-70%29%2F2\"
\n" ); document.write( "\"x+=+25\" or \"x+=+-35\"\r
\n" ); document.write( "\n" ); document.write( "But since we are looking for a real positive number, let us take \"x+=+25\" as our answer. Therefore, the width is 25 ft and the length is 35 ft.\r
\n" ); document.write( "\n" ); document.write( "Thank you. ~kmcruz09~\r
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