document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1143708>Question 1143708</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The average of a set of 6 numbers is 3.5. If the number is 4.2 is added to the set , what is the average of the new set of numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #764600 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=764600\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The solution by tutor @ikleyn shows what is probably the standard way for solving a problem like this.<br><BR>\n" );
document.write( "Here is another method that I often use in problems like this involving averages of numbers that are \"close together\".<br><BR>\n" );
document.write( "Try it and see if it \"works\" for you.<br><BR>\n" );
document.write( "(1) The new number is 4.2-3.5 = 0.7 greater than the current average.<BR>\n" );
document.write( "(2) To get the new average, that additional 0.7 has to be divided evenly among what is now 7 numbers.<BR>\n" );
document.write( "(3) That means the new average is larger by 0.7/7 = 0.1 -- so the new average is 3.5+0.1 = 3.6. </SPAN>\n" );
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