document.write( "Question 1143682: A portion of a wire 70 inches in length is bent to form a rectangle having the greatest possible area such that length of the rectangle exceeds three times its width by 2 inches, and the dimensions of the rectangle are whole numbers. Find the length of the wire that is NOT used to form the rectangle.\r
\n" ); document.write( "\n" ); document.write( "So, I let w represent the width.
\n" ); document.write( "The length, therefore, would be 3w+2
\n" ); document.write( "And perimeter = 2L+2W\r
\n" ); document.write( "\n" ); document.write( "Therefore, I have 2(3w+2)+2w=70
\n" ); document.write( "Then 6W+4+2W=70
\n" ); document.write( "Then 8W+4=70
\n" ); document.write( "Then 8W=66
\n" ); document.write( "And finally, 66 divided by 8 is 8 with a remainder of 2.\r
\n" ); document.write( "\n" ); document.write( "So, is 2 inches the length of the wire that was not used? Is my work correct?
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Algebra.Com's Answer #764562 by ikleyn(52787)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "Your work and your final answer are both correct.\r
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\n" ); document.write( "\n" ); document.write( "The only thing you forgot to mention, is THIS :\r
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document.write( "    At given condition, to maximize the area of the rectangle, you should choose W as great as possible, satisfying other constraints\r\n" );
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document.write( "    (the other constraint is to have integer length and width).\r\n" );
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\n" ); document.write( "\n" ); document.write( "The rest is OK.\r
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\n" ); document.write( "\n" ); document.write( "My congrats (!)\r
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\n" ); document.write( "\n" ); document.write( "Good work (!)\r
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\n" ); document.write( "\n" ); document.write( "Come again soon (!)\r
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