document.write( "Question 105084: Good evening tutor can you tell me if I have this problem correct? \r
\n" ); document.write( "\n" ); document.write( "THe length of the retangle is 2 cm more than 5 times its width. If the area of the rectangle is 65 cm^2, find the width of the rectangle to the nearest hundredth. \r
\n" ); document.write( "\n" ); document.write( "Could you tell me if the answer is 3.41 cm? Thanks for your help.
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Algebra.Com's Answer #76456 by Earlsdon(6294)\"\" \"About 
You can put this solution on YOUR website!
Let L = the length and W = the width.
\n" ); document.write( "From the problem description, you can write:
\n" ); document.write( "L = 5W+2 \"The length (L) of the rectangle is (=) 2 more (+2) than 5 times its width (5W)\"
\n" ); document.write( "A = 65 sq.cm. \"The area of the rectangle is 65 sq.cm.\"
\n" ); document.write( "The formula for the area of a rectangle is:
\n" ); document.write( "A = L*W Make the appropriate substitutions.
\n" ); document.write( "\"65+=+%285W%2B2%29%2AW\" Simplify and solve for W.
\n" ); document.write( "\"65+=+5W%5E2+%2B+2W\" Subtract 65 from both sides.
\n" ); document.write( "\"5W%5E2%2B2W-65+=+0\" Use the quadratic formula to solve for W.
\n" ); document.write( "\"W+=+%28-2%2B-sqrt%282%5E2-4%285%29%28-65%29%29%29%2F2%285%29\"
\n" ); document.write( "\"W+=+-3.811\" Discard the negative solution.
\n" ); document.write( "\"W+=+3.411\"
\n" ); document.write( "The width is 3.41 cm
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