document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=105029>Question 105029</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Perform the indicated calculations. Write the result in scientific<BR>\n" );
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document.write( "4.5 * 10^12/1.5 * 10^7\r<BR>\n" );
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document.write( "Thank you for your help.. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76453 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%284.5+%2A+10%5E12%29%2F%281.5+%2A+10%5E7%29 ALIGN=MIDDLE  ALT=\"%284.5+%2A+10%5E12%29%2F%281.5+%2A+10%5E7%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The numerator has two factors ... <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4.5 ALIGN=MIDDLE  ALT=\"4.5\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%5E12 ALIGN=MIDDLE  ALT=\"10%5E12\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The denominator also has two factors ... <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.5 ALIGN=MIDDLE  ALT=\"1.5\"   DISABLED_style= \"max-width:90%; height:auto;\" > and <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%5E7 ALIGN=MIDDLE  ALT=\"10%5E7\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "The way to do this problem is to divide the factor <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1.5 ALIGN=MIDDLE  ALT=\"1.5\"   DISABLED_style= \"max-width:90%; height:auto;\" > in the denominator into the<BR>\n" );
document.write( "factor <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=4.5 ALIGN=MIDDLE  ALT=\"4.5\"   DISABLED_style= \"max-width:90%; height:auto;\" > in the numerator.  The result of this division is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3.0 ALIGN=MIDDLE  ALT=\"3.0\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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document.write( "Then divide the factor <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%5E7 ALIGN=MIDDLE  ALT=\"10%5E7\"   DISABLED_style= \"max-width:90%; height:auto;\" > in the denominator into the factor <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%5E12 ALIGN=MIDDLE  ALT=\"10%5E12\"   DISABLED_style= \"max-width:90%; height:auto;\" > in the<BR>\n" );
document.write( "numerator. Since these two factors both have the base <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10 ALIGN=MIDDLE  ALT=\"10\"   DISABLED_style= \"max-width:90%; height:auto;\" > the division just involves<BR>\n" );
document.write( "subtracting the exponent of the denominator from the exponent of the numerator. The result is:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=10%5E12%2F10%5E7+=+10%5E%2812-7%29+=+10%5E5 ALIGN=MIDDLE  ALT=\"10%5E12%2F10%5E7+=+10%5E%2812-7%29+=+10%5E5\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
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document.write( "Combining these two results leads to the answer of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3.0+%2A+10%5E5 ALIGN=MIDDLE  ALT=\"3.0+%2A+10%5E5\"   DISABLED_style= \"max-width:90%; height:auto;\" > and this is in scientific<BR>\n" );
document.write( "notation.<BR>\n" );
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document.write( "Hope this helps you to see how to work the problem.<BR>\n" );
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