document.write( "Question 1143657: Find the equation of the circle that passes through the points of intersection of the circles x²+y²=2x, x²+y²=2y and has its center on the line y=2. \n" ); document.write( "
Algebra.Com's Answer #764527 by Alan3354(69443)\"\" \"About 
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Find the equation of the circle that passes through the points of intersection of the circles x²+y²=2x, x²+y²=2y and has its center on the line y=2.
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\n" ); document.write( "Find the 2 points of intersection.
\n" ); document.write( "They're (0,0) and (1,1)
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\n" ); document.write( "The center is on the perpendicular bisector of y=x thru the 2 points ---> slope = -1 thru the point (1/2,1/2)
\n" ); document.write( "---> y - 0.5 = -1*(x - 0.5)
\n" ); document.write( "y = -x + 1
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\n" ); document.write( "The center is the intersection of y = -x + 1 and y = 2
\n" ); document.write( "2 = -x + 1
\n" ); document.write( "x = -1
\n" ); document.write( "y = 2
\n" ); document.write( "---> the center is (-1,2)
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\n" ); document.write( "r = the distance from (-1,2) to either point.
\n" ); document.write( "r = sqrt(5)
\n" ); document.write( "The circle is \"%28x%2B1%29%5E2+%2B+%28y-2%29%5E2+=+5\"\r
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