document.write( "Question 105081: I have two questions\r
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document.write( "#1-After inheriting some money, a woman wants to invest enough to have an annual income of $5,000. If she can invest $20,000 at 9% annual interest, how much more will she have to invest at 7% to achieve her goal?\r
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document.write( "#2-Equal amounts are invested at 6%, 7%, and 8% annual interest, if the three investments yield total of $2,037 annual interest, find the total investment. \n" );
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Algebra.Com's Answer #76451 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! .09*20,000+.07X=5,000 \n" ); document.write( "1,800+.07X=5,000 \n" ); document.write( ".07X=5,000-1,800 \n" ); document.write( ".07X=3,200 \n" ); document.write( "X=3,200/.07 \n" ); document.write( "X=45,714.29 IS THE AMOUNT INVESTED @ 7% TO ACHIEVE THE REQUIRED INCOME. \n" ); document.write( "PROOF \n" ); document.write( ".09*5,000+.07*45,714.29=5,000 \n" ); document.write( "1,800+3,200=5,000 \n" ); document.write( "5,000=5,000 \n" ); document.write( "-------------------------------------------------------- \n" ); document.write( ".06X+.07X+.08X=2,037 \n" ); document.write( ".21X=2,037 \n" ); document.write( "X=2,037/.21 \n" ); document.write( "X=9,700 INVESTED @ EACH RATE OF 6%, 7% & 8%. \n" ); document.write( "3*9,700=29,100 IS THE TOTAL AMOUNT INVESTED. \n" ); document.write( "PROOF \n" ); document.write( ".06*9,700+.07*9,700+.08*9,700=2,037 \n" ); document.write( "582+679+776=2,037 \n" ); document.write( "2,037=2,037 \n" ); document.write( " \n" ); document.write( " |