document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=105078>Question 105078</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the equation of the line perpendicular to -8x+2y=-2 that contains point (-5,8) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #76449 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=76449\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> FIRST WE NEED TO FIND THE SLOPE OF THE GIVEN LINE USING ---<BR>\n" );
document.write( "Y=mX+b WHERE m=SLOPE & b= THE Y INTERCEPT.<BR>\n" );
document.write( "-8X+2Y=-2<BR>\n" );
document.write( "2Y=8X-2<BR>\n" );
document.write( "Y=8X/2-2/2<BR>\n" );
document.write( "Y=4X-1 THUS THIS EQUATION HAS A SLOPE (m)=4.<BR>\n" );
document.write( "A PERPENDICULAR LINE WILL HAVE A SLOPE OF THE NEGATIVE RECIPRICAL OF THIS SLOPE:<BR>\n" );
document.write( "THUS THE PERPENDICULAR LINE HAS A SLOPE=-1/4.<BR>\n" );
document.write( "NOW REPLACE THE X & Y TERMS BY -5 & 8 & SOLVE FOR b.<BR>\n" );
document.write( "8=-1/4*-5+b<BR>\n" );
document.write( "8=5/4+b<BR>\n" );
document.write( "b=8-5/4<BR>\n" );
document.write( "b=(32-5)/4<BR>\n" );
document.write( "b=27/4 THIS IS THE Y INTERCEPT OF THE PERPENDICULAR LINE THROUGH THE POINT <BR>\n" );
document.write( "(-5,8). <BR>\n" );
document.write( "Y=-X/4+27/4 IS THE DESIRED EQUATION.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );