document.write( "Question 1143508: A businessman borrowed P3,000,000 with interest at the rate of 6% compounded annually. He agrees to discharge his obligations by paying series of 6 annual payment,the first being due at the end of the fifth year. Determine the value of his annual payment. \n" ); document.write( "
Algebra.Com's Answer #764465 by Theo(13342)![]() ![]() You can put this solution on YOUR website! he will make 6 payments at the end of each year starting from the end of the firth year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the interest rate is 6% per year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the present value of the loan is 3,000,000 at the end of year 0.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the end of year 0 is the same time point as the beginning of year 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the future value of this loan at the end of year 4 is equal to 3,000,000 * 1.06^4 = 3,787,430.88.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3,787,430.88 is the present value of the loan at the end of year 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the end of year 4 is the same time point as the beginning of year 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "there are 6 annual payments starting at the end of year 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "what you have, therefore, is the following inputs to a financial calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "present value = 3,787,430.88. \n" ); document.write( "future value = 0 \n" ); document.write( "number of time periods = 6 \n" ); document.write( "interest rate per time period = 6% \n" ); document.write( "payments are made at the end of each time period.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the calculator then tells you that the payments at the end of year year need to be 770,221.90.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that is your solution.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the calculator i used can be found at https://arachnoid.com/finance/\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a display of the results using this calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "i also did a cash flow analysis using excel.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a display of the results of that cash flow analysis.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "boy means beginning of year. \n" ); document.write( "eoy means end of year.\r \n" ); document.write( "\n" ); document.write( "these are the time points.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the beginning of year 1 is the same time point as the end of year 0. \n" ); document.write( "the beginning of year 5 is the same time point as the end of year 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "column F is the loan \n" ); document.write( "column G is the payments on that loan. \n" ); document.write( "column H is the remaining balance of the loan.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the calculations for the remaining balance of the loan are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the remaining balance of the loan at the end of year 0 is the loan itself.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the remaining balance of the loan at the end of yer 1 is the value of the loan at the end of year 0 * 1.06 minus any payment at the end of year 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this continues for each year.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "at the end of year 5, the remaining balance of the loan is equal to value of the loan at the end of year 4 * 1.06 minus the value of the payment at the end of year 5.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this becomes $3,787,430.88 * 1.06 = $4,014,676.733 - $770,221.90 = $3,244,454.833, shown as $3,244,454.83.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this same procedure continues to the end of the loan period where the remaining balance is $.01.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "it is actually $0.00 but there is a small error due to rounding of the payment amount.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the actual values, without rounding are:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |