document.write( "Question 1143570: If the numerator of a fraction is increased by 2 and the denominator by 1, it becomes 1. In case the numerator is decreased by 4 and the denominator by 2, it becomes 1/2. Find the fraction. \n" ); document.write( "
Algebra.Com's Answer #764408 by mathmadeeasy(2)\"\" \"About 
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Given equations:\r
\n" ); document.write( "\n" ); document.write( "1. x+2/y+1 = 1
\n" ); document.write( "*multiply both sides by y+1
\n" ); document.write( " x+2 = y+1
\n" ); document.write( " x = y-1\r
\n" ); document.write( "\n" ); document.write( "2. x-4/y-2 = 1/2
\n" ); document.write( " 2(x-4) = 1(y-2)
\n" ); document.write( " 2x-8 = y-2
\n" ); document.write( " 2x = y+6
\n" ); document.write( "*insert x = y-1 to equation above
\n" ); document.write( " 2(y-1)= y+6
\n" ); document.write( " 2y-2 = y+6
\n" ); document.write( " y = 8
\n" ); document.write( " So therefore, using x = y-1
\n" ); document.write( " x = 8-1
\n" ); document.write( " x = 7\r
\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "x = 7
\n" ); document.write( "y = 8\r
\n" ); document.write( "\n" ); document.write( "Testing:
\n" ); document.write( "x = 7 + 2 = 9
\n" ); document.write( "y = 8 + 1 = 9
\n" ); document.write( "9/9 = 1\r
\n" ); document.write( "\n" ); document.write( "x = 7 - 4 = 3
\n" ); document.write( "y = 8 - 2 = 6
\n" ); document.write( "3/6 = 1/2
\n" ); document.write( "
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