document.write( "Question 1143570: If the numerator of a fraction is increased by 2 and the denominator by 1, it becomes 1. In case the numerator is decreased by 4 and the denominator by 2, it becomes 1/2. Find the fraction. \n" ); document.write( "
Algebra.Com's Answer #764408 by mathmadeeasy(2)![]() ![]() ![]() You can put this solution on YOUR website! Given equations:\r \n" ); document.write( "\n" ); document.write( "1. x+2/y+1 = 1 \n" ); document.write( "*multiply both sides by y+1 \n" ); document.write( " x+2 = y+1 \n" ); document.write( " x = y-1\r \n" ); document.write( "\n" ); document.write( "2. x-4/y-2 = 1/2 \n" ); document.write( " 2(x-4) = 1(y-2) \n" ); document.write( " 2x-8 = y-2 \n" ); document.write( " 2x = y+6 \n" ); document.write( "*insert x = y-1 to equation above \n" ); document.write( " 2(y-1)= y+6 \n" ); document.write( " 2y-2 = y+6 \n" ); document.write( " y = 8 \n" ); document.write( " So therefore, using x = y-1 \n" ); document.write( " x = 8-1 \n" ); document.write( " x = 7\r \n" ); document.write( "\n" ); document.write( "Answer: \n" ); document.write( "x = 7 \n" ); document.write( "y = 8\r \n" ); document.write( "\n" ); document.write( "Testing: \n" ); document.write( "x = 7 + 2 = 9 \n" ); document.write( "y = 8 + 1 = 9 \n" ); document.write( "9/9 = 1\r \n" ); document.write( "\n" ); document.write( "x = 7 - 4 = 3 \n" ); document.write( "y = 8 - 2 = 6 \n" ); document.write( "3/6 = 1/2 \n" ); document.write( " |