document.write( "Question 1143540: A furniture shop refinishes tables. Employees use two methods to refinish tables. Method I takes 0.5 hours and the material costs $10. Method II takes 2.0 hours, and the material costs $4. Next week, they plan to spend 85 hours in labor and $476 in material for refinishing tables. How many tables should they plan to refinish with each method? \n" ); document.write( "

Algebra.Com's Answer #764363 by ikleyn(52776) $\"\"$ $\"About$

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document.write( "Let x= the number of tables by Method I and y = the number of tables by Method II.\r\n" );
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document.write( "The condition / (assumption) that all resources are used, gives these two equations\r\n" );
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document.write( "    0.5x + 2y =  85      (hours used)     (1)\r\n" );
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document.write( "     10x + 4y = 476      (money used)     (2)\r\n" );
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document.write( "Solve it by the Elimination method to get the \r\n" );
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document.write( "Fortunately, it has the solution in integer numbers.\r\n" );
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document.write( "ANSWER.   x= 34 tables by the Method I  and  y= 34 tables by the Method II.\r\n" );
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