document.write( "Question 1143506: In a survey concerning the smoking habits of consumer it was found that 55% smoke cigarette A, 50% smoke cigarette B,40% smoke cigarette C, 30% smoke cigarettes A and B, 20% smoke cigarettes A and C, 12% smoke cigarettes B and
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Algebra.Com's Answer #764344 by ikleyn(52802)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "            Your formulation is not accurate.\r
\n" ); document.write( "\n" ); document.write( "            To be accurate (and to become a true Math problem),  it has to be re-written and re-edited.\r
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document.write( "            In a survey concerning the smoking habits of consumer it was found that \r\n" );
document.write( "            55% smoke cigarette A, 50% smoke cigarette B,40% smoke cigarette C, \r\n" );
document.write( "            30% smoke cigarettes A and B, 20% smoke cigarettes A and C, 12% smoke cigarettes B and C,\r\n" );
document.write( "            while only 10% smoke all three types of cigarettes. What percentage of the population did not smoke? \r\n" );
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\n" ); document.write( "\n" ); document.write( "            The solution is below.\r
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document.write( "The percentage of those who smoke at least one of the three types of cigarettes is\r\n" );
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document.write( "    55 + 50 + 40 - 30 - 20 - 12 + 10 = 93  percents.      (*)\r\n" );
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document.write( "Therefore, 7% of the population do not smoke.      ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "The key to the solution is this alternate sum in the left side of (*).\r
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\n" ); document.write( "\n" ); document.write( "For this formula, see the lessons\r
\n" ); document.write( "\n" ); document.write( "    - Advanced problems on counting elements in sub-sets of a given finite set\r
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