document.write( "Question 1143482: James can jog twice as fast as he can walk. He was able to jog the first 9 miles to his grandmother’s house, but then he tired and walked the remaining 1.5 miles. If the total trip took 2 hours, then what was his average jogging speed? \n" ); document.write( "
Algebra.Com's Answer #764290 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! James can jog twice as fast as he can walk. \n" ); document.write( " He was able to jog the first 9 miles to his grandmother’s house, but then he tired and walked the remaining 1.5 miles. \n" ); document.write( " If the total trip took 2 hours, then what was his average jogging speed? \n" ); document.write( ": \n" ); document.write( "let j = his jogging speed \n" ); document.write( "he walks half as fast, therefore \n" ); document.write( ".5j = his walking speed \n" ); document.write( ": \n" ); document.write( "write a time equation, time = dist/speed \n" ); document.write( "jog time + walk time = 2 hrs \n" ); document.write( " \n" ); document.write( "multiply by .5j \n" ); document.write( ".5(9) + (1.5) = .5j(2) \n" ); document.write( "4.5 + .1.5 = j \n" ); document.write( "6 = j \n" ); document.write( "j = 6 mph is the jogging speed \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check, find the actual time of each \n" ); document.write( "9/6 = 1.5 hrs \n" ); document.write( "1.5/3 = .5 hrs \n" ); document.write( "----------------- \n" ); document.write( "total time 2 hrs \n" ); document.write( " \n" ); document.write( " |