document.write( "Question 1143425: The graph of tan(T) is shifted right 90° and has the period increased to 360°. What is the transformed equation? \n" ); document.write( "
Algebra.Com's Answer #764252 by Edwin McCravy(20060)\"\" \"About 
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document.write( "\"tan%28A%28T%2BB%29%5E%22%22%29\" is shifted |B| units left if B is positive and\r\n" );
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document.write( "|B| units right is B is negative. so to shift it right 90°, B has to\r\n" );
document.write( "be negative.  So the equation has it has to be of this form:\r\n" );
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document.write( "\"tan%28A%28T-90%5Eo%29%5E%22%22%29\"  \r\n" );
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document.write( "The period of \"tan%28A%28T%2BB%29%5E%22%22%29\" is \"180%5Eo%2FA\" so to make the\r\n" );
document.write( "period 360°, we must have\r\n" );
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document.write( "\"180%5Eo%2FA=360%5Eo\"\r\n" );
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document.write( "Multiply both sides by A\r\n" );
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document.write( "\"180%5Eo=360%5Eo%2AA\"\r\n" );
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document.write( "\"180%5Eo%2F360%5Eo=A\"\r\n" );
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document.write( "\"1%2F2=A\"\r\n" );
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document.write( "\"tan%28expr%281%2F2%29%28T-90%5Eo%29%5E%22%22%29\"  <---answer\r\n" );
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document.write( "Edwin
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