document.write( "Question 1143442: Two buses leave the Cubao Terminal at the same time bound for the Bicol Region. Bus A travels at the speed of 90 kilometers per hour (kph) while Bus B travels at 100 Kph. How many minutes will the two buses be 10 kilometers apart? \n" ); document.write( "
Algebra.Com's Answer #764250 by ikleyn(52798)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Their relative speed is 100 km/h - 90 km/h = 10 km/h, which means that the bus B runs away from the bus A at the rate of 10 km/h.\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the two buses will be 10 km apart in 1 hour, i.e. in 60 minutes.\r
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document.write( "In algebra language, the distance between the buses is  100*t - 90*t  kilometers,\r\n" );
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document.write( "and it will be 10 kilometers at the time t\r\n" );
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document.write( "    100t - 90t = 10,    or\r\n" );
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document.write( "     10t       = 10\r\n" );
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document.write( "       t       = \"10%2F10\" = 1 hour = 60 minutes.      ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "See introductory lessons on Travel and Distance problems\r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems \r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems for two bodies moving in opposite directions \r
\n" ); document.write( "\n" ); document.write( "    - Travel and Distance problems for two bodies moving in the same direction (catching up)\r
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\n" ); document.write( "\n" ); document.write( "They are written specially for you.\r
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\n" ); document.write( "\n" ); document.write( "You will find the solutions of many similar problems there.\r
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\n" ); document.write( "\n" ); document.write( "Read them and learn once and for all from these lessons on how to solve simple Travel and Distance problems.\r
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\n" ); document.write( "\n" ); document.write( "Become an expert in this area.\r
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