document.write( "Question 1143407: Suppose a railroad rail is 4 kilometers and it expands on a hot day by 13 centimeters in length. Approximately how many meters would the center of the rail rise above the​ ground? \n" ); document.write( "
Algebra.Com's Answer #764217 by ankor@dixie-net.com(22740)\"\" \"About 
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Suppose a railroad rail is 4 kilometers and it expands on a hot day by 13 centimeters in length.
\n" ); document.write( " Approximately how many meters would the center of the rail rise above the​ ground?
\n" ); document.write( ":
\n" ); document.write( "change 4 km to 4000 meters, change 13 cm to .13 meters
\n" ); document.write( "this would form an isosceles triangle with a base of 4000 meters
\n" ); document.write( "then
\n" ); document.write( "\"%284000%2B.13%29%2F2\" = 2000.065 meters, the equal sides
\n" ); document.write( "the altitude (a) of the triangle = the center of the rail rise
\n" ); document.write( ":
\n" ); document.write( "Using pythag on one of the two right triangles that are formed
\n" ); document.write( "a^2 + 2000^2 = 2000.065^2
\n" ); document.write( ":
\n" ); document.write( "a = \"sqrt%282000.065%5E2+-+2000%5E2%29\"
\n" ); document.write( "a = 16 meters approximately
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