document.write( "Question 1143372: One root of \"+x%5E2-3x%2Bk-2=0+\" is -4. Find the value of k.\r
\n" ); document.write( "\n" ); document.write( "Here is what I tried at the start:
\n" ); document.write( "\"+-4=-3%2B-+sqrt%289-4%28k-2%29%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "But I am stuck from there on. Thank you for your help!
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Algebra.Com's Answer #764182 by MathTherapy(10556)\"\" \"About 
You can put this solution on YOUR website!
One root of \"+x%5E2-3x%2Bk-2=0+\" is -4. Find the value of k.\r
\n" ); document.write( "\n" ); document.write( "Here is what I tried at the start:
\n" ); document.write( "\"+-4=-3%2B-+sqrt%289-4%28k-2%29%29%2F2+\"\r
\n" ); document.write( "\n" ); document.write( "But I am stuck from there on. Thank you for your help!
\n" ); document.write( "
You could use the quadratic equation formula, but I prefer the method below:
\n" ); document.write( "You may remember that:
\n" ); document.write( "Let's call the other root: R2. We can see from the quadratic equation that: a = 1; b = - 3, and c = k - 2
\n" ); document.write( "We then get:
\n" ); document.write( "We also get:
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\n" ); document.write( "AND an even easier method is the REMAINDER THEOREM method used by TUTOR @Rothauserc, which should actually be:
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