document.write( "Question 1143333: A promissory note will pay $59,000 at maturity 21 years from now. If you pay $20,000 for the note now, what rate compounded continuously would you earn? \n" ); document.write( "
Algebra.Com's Answer #764125 by Theo(13342)\"\" \"About 
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continuous compounding formula is f = p * e ^ (r * t)\r
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\n" ); document.write( "\n" ); document.write( "f = future value = 59,000
\n" ); document.write( "p = present value = 20,000
\n" ); document.write( "n = 21\r
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\n" ); document.write( "\n" ); document.write( "you want to solve for r.\r
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\n" ); document.write( "\n" ); document.write( "formula becomes 59,000 = 20,000 * e ^ (r * 21)\r
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\n" ); document.write( "\n" ); document.write( "divide both sides of he formula by 20,000 to get 2.95 = e ^ (r * 21)\r
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\n" ); document.write( "\n" ); document.write( "take the natural log of both sides of the equation to get ln(2.95) = ln(e ^ (r * 21))\r
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\n" ); document.write( "\n" ); document.write( "since ln(e ^ (r * 21) = r * 21 * ln(e) and since ln(e) = 1, the formula becomes:\r
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\n" ); document.write( "\n" ); document.write( "ln(2.95) = r * 21\r
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\n" ); document.write( "\n" ); document.write( "solve for r to get r = ln(2.95) / 21 = 0.051514532\r
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\n" ); document.write( "\n" ); document.write( "confirm by replacing r in the original equation to get:\r
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\n" ); document.write( "\n" ); document.write( "59,000 = 20,000 * e ^ 0.051514532 * 21)\r
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\n" ); document.write( "\n" ); document.write( "this results in 50,000 = 50,000, confirming the solution is correct.\r
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