document.write( "Question 1143230: evaluate sqrt((4+4cos2x/1-cos2x)) \n" ); document.write( "
Algebra.Com's Answer #764073 by 4419875(21)\"\" \"About 
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Remember that:
\n" ); document.write( "\"sin%5E2%28x%29%2Bcos%5E2%28x%29=1\"
\n" ); document.write( "and
\n" ); document.write( "\"cos2x+=+cos%5E2%28x%29-sin%5E2%28x%29\"\r
\n" ); document.write( "\n" ); document.write( "Now before substituting any value, factor out first the numerator:
\n" ); document.write( "\"sqrt%284%281%2Bcos2x%29%2F%281-cos2x%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Then, now we take the square root of 4 and substitute the equivalent functions:
\n" ); document.write( "\r
\n" ); document.write( "\n" ); document.write( "Solve the expression:
\n" ); document.write( "1.
\n" ); document.write( "2.\"sqrt%284%282cos%5E2%28x%29%29%29%2F%282sin%5E2%28x%29%29%29\"
\n" ); document.write( "3. Now cancel out 2 and you may find the equivalent in the form of \"cot%5E2%28x%29\"
\n" ); document.write( "4. Lastly get the sqrt of the expression \"sqrt%284+cot%5E2%28x%29%29\"\r
\n" ); document.write( "\n" ); document.write( "ANSWER: \"2+cot%28x%29\"
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