document.write( "Question 104958: find the domain for the following: \r
\n" ); document.write( "\n" ); document.write( "f(x) = sqrt (3x-4)\r
\n" ); document.write( "\n" ); document.write( "g(x) = (-2x+1) / (1-3x)\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

Algebra.Com's Answer #76407 by Fombitz(32388) $\"\"$ $\"About$

You can put this solution on YOUR website!
For the first function,
\n" ); document.write( " $\"f%28x%29=sqrt%283x-4%29\"$
\n" ); document.write( "the value inside the square root must always be greater than or equal to zero for the function to be defined.
\n" ); document.write( " $\"3x-4%3E=0\"$
\n" ); document.write( " $\"3x%3E=4\"$
\n" ); document.write( " $\"x%3E=4%2F3\"$ The domain for $\"f%28x%29=sqrt%283x-4%29\"$
\n" ); document.write( "For the second function,
\n" ); document.write( " $\"g%28x%29+=+%28-2x%2B1%29+%2F+%281-3x%29\"$
\n" ); document.write( "you need to avoid any values that make the denominator zero since division by zero is undefined.
\n" ); document.write( " $\"1-3x=0\"$
\n" ); document.write( " $\"1=3x\"$
\n" ); document.write( " $\"x=1%2F3\"$
\n" ); document.write( "In this case, all values are acceptable except x=1/3.
\n" ); document.write( " $\"x%3C1%2F3\"$ and $\"x%3E1%2F3\"$ is the domain for $\"g%28x%29=+%28-2x%2B1%29+%2F+%281-3x%29\"$ \n" ); document.write( "

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