document.write( "Question 1143269: 3/4-1/2 \n" ); document.write( "
Algebra.Com's Answer #764062 by Alan3354(69443)\"\" \"About 
You can put this solution on YOUR website!
3/4-1/2
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\n" ); document.write( "For problems like this with 2 terms:
\n" ); document.write( "\"a%2Fb+-+c%2Fd+=+%28ad+-+bc%29%2Fbd\"
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\n" ); document.write( "---> \"%283%2A2+-+4%2A1%29%2F%284%2A2%29+=+%286-4%29%2F8+=+2%2F8+=+1%2F4\"
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\n" ); document.write( "I remember the LCD, Least Common Denominator from grade school.
\n" ); document.write( "It's a waste of time.
\n" ); document.write( "It's not relevant to this example, but is for some other problems.
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\n" ); document.write( "For example:
\n" ); document.write( "\"3%2F4+%2B+1%2F3+%2B+5%2F6\"
\n" ); document.write( "The LCD is 12, but there's no good reason to waste time finding it.
\n" ); document.write( "Use the product of the 3 DENs': 4*3*6 = 72
\n" ); document.write( "--> \"54%2F72+%2B+24%2F72+%2B+60%2F72+=+138%2F72\"
\n" ); document.write( "Then reduce.
\n" ); document.write( "= \"23%2F12\"
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\n" ); document.write( "Another example:
\n" ); document.write( "\"4%2Fa+%2B+b%2Fc+%2B+5%2Fac\"
\n" ); document.write( "Use the product: \"a%2Ac%2Aac+=+a%5E2c%5E2\"
\n" ); document.write( "---> \"%284ac%5E2+%2B+b%2Aa%5E2c+%2B+5ac%29%2Fa%5E2c%5E2\"
\n" ); document.write( "= \"%284ac%5E2+%2B+a%5E2bc+%2B+5ac%29%2Fa%5E2c%5E2\"
\n" ); document.write( "= \"%284ac+%2B+a%5E2b+%2B+5a%29%2Fa%5E2c\"
\n" ); document.write( "= \"%284c+%2B+ab+%2B+5%29%2Fac\"
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\n" ); document.write( "Using the product and reducing the result takes less time than finding the LCD in most cases.
\n" ); document.write( "IDK why schools and texts persist with the LCD.
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