document.write( "Question 104951: Value of car 2 yrs after it was bought = 14300, 4 yrs = 10200, what is depreciation rate? Is 2050 right and how do you find the yrs it will take to reach 0 value. I tried but now I am stuck. Please help if you will, and thanks again for the help!!! \n" ); document.write( "
Algebra.Com's Answer #76403 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
The assumption is that the depreciation rate is linear.
\n" ); document.write( "2 yrs after = $14,300
\n" ); document.write( "4 yrs after = $10,200
\n" ); document.write( "Depreciation Rate = DR
\n" ); document.write( "DR=(Value(2)-Value(1))/(Time(2)-Time(1))
\n" ); document.write( "DR = ($10200-$14300)/(4-2)yr
\n" ); document.write( "DR = -$2050/yr.
\n" ); document.write( "The negative rate means that you lose value as time goes on, that is, depreciates.
\n" ); document.write( "If you look at the DR equation, it looks like a slope calculation.
\n" ); document.write( "In fact, the rate is the slope of the value function, V(t).
\n" ); document.write( "Let's find the intercept.
\n" ); document.write( "\"V%28t%29+=+mt%2Bb\"
\n" ); document.write( "\"V%28t%29+=+-2050t%2Bb\"
\n" ); document.write( "At 2 years,
\n" ); document.write( "\"V%282%29+=+-2050%282%29%2Bb+=+14300\"
\n" ); document.write( "\"b=14300+%2B+2%282050%29\"
\n" ); document.write( "\"b=18400\"
\n" ); document.write( "\"V%28t%29=18400-2050t\"
\n" ); document.write( "At t=0 years, the car is brand new and its value was $18,400.
\n" ); document.write( "When V(t)=0, what will t be?
\n" ); document.write( "\"18400-2050t=0\"
\n" ); document.write( "\"-2050t=-18400\"
\n" ); document.write( "t=8.97 years, almost 9 years old.
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