document.write( "Question 104951: Value of car 2 yrs after it was bought = 14300, 4 yrs = 10200, what is depreciation rate? Is 2050 right and how do you find the yrs it will take to reach 0 value. I tried but now I am stuck. Please help if you will, and thanks again for the help!!! \n" ); document.write( "
Algebra.Com's Answer #76403 by Fombitz(32388) You can put this solution on YOUR website! The assumption is that the depreciation rate is linear. \n" ); document.write( "2 yrs after = $14,300 \n" ); document.write( "4 yrs after = $10,200 \n" ); document.write( "Depreciation Rate = DR \n" ); document.write( "DR=(Value(2)-Value(1))/(Time(2)-Time(1)) \n" ); document.write( "DR = ($10200-$14300)/(4-2)yr \n" ); document.write( "DR = -$2050/yr. \n" ); document.write( "The negative rate means that you lose value as time goes on, that is, depreciates. \n" ); document.write( "If you look at the DR equation, it looks like a slope calculation. \n" ); document.write( "In fact, the rate is the slope of the value function, V(t). \n" ); document.write( "Let's find the intercept. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "At 2 years, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "At t=0 years, the car is brand new and its value was $18,400. \n" ); document.write( "When V(t)=0, what will t be? \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "t=8.97 years, almost 9 years old. \n" ); document.write( " \n" ); document.write( " |