document.write( "Question 1143210: Solution to this problem:
\n" ); document.write( "Tim's age plus Cheryl's age is 80.
\n" ); document.write( "Tim's age plus Greg's age is 98.
\n" ); document.write( "Cheryl's age plus Greg's age is 94. What are their ages? \n" ); document.write( "
Algebra.Com's Answer #764012 by greenestamps(13198)\"\" \"About 
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\n" ); document.write( "You are given the sums of the three ages two at a time:
\n" ); document.write( "T+C = 80
\n" ); document.write( "T+G = 98
\n" ); document.write( "C+G = 94

\n" ); document.write( "You already have two good algebraic solutions; here is another method that might be a bit less work.

\n" ); document.write( "(1) Add all three equations: 2(T+C+G) = 272
\n" ); document.write( "(2) Divide by 2: T+C+G = 136

\n" ); document.write( "Now the age of each can be found by comparing this last equation to the original three equations:
\n" ); document.write( "G = (T+C+G)-(T+C) = 136-80 = 56
\n" ); document.write( "C = (T+C+G)-(T+G) = 136-98 = 38
\n" ); document.write( "T = (T+C+G)-(C+G) = 136-94 = 42 \n" ); document.write( "
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