document.write( "Question 1143095: The pizza delivery department receives 75% brand pizza orders. Find the probability that among 100 received orders there will be (a) 72 brand pizza orders; (b) from 70 to 78 brand pizza orders. (c) Find the most probable number of brand pizza orders. \n" ); document.write( "

Algebra.Com's Answer #763987 by Boreal(15235) $\"\"$ $\"About$

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The most probable number is 100*0.75 or 75\r
\n" ); document.write( "\n" ); document.write( "for 72, it is 100C72*0.75^72*0.25^28=0.0701\r
\n" ); document.write( "\n" ); document.write( "use normal approximation for 70 to 78 but could use the above approach 9 times and add.\r
\n" ); document.write( "\n" ); document.write( "mean is 75
\n" ); document.write( "variance is 75*.25=18.75
\n" ); document.write( "sd is sqrt (V)=4.33
\n" ); document.write( "for 70, use correction factor of 69.5
\n" ); document.write( "z=(69.5-75)/4.33 or -1.27
\n" ); document.write( "and
\n" ); document.write( "z=(78.5-75)/4.33=+0.81
\n" ); document.write( "that probability is 0.6890 \n" ); document.write( "

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