document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1143194>Question 1143194</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Fill in the missing values to make the equations true.<BR>\n" );
document.write( "The ? are the missing value\r<BR>\n" );
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document.write( "(a)log9^8 + log9^7 = log9 ?   \r<BR>\n" );
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document.write( "(b)log4^3 -log4? = log4^3/7 \r<BR>\n" );
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document.write( "(c)3 log8^3 =log8 ?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #763977 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=763977\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Use your basic log rules:<br><BR>\n" );
document.write( "log(ab) = log(a)+log(b)<BR>\n" );
document.write( "log(a/b) = log(a)-log(b)<BR>\n" );
document.write( "log(a^b) = b*log(a) </SPAN>\n" );
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