document.write( "Question 1143121: Lea’s school is selling tickets for the upcoming choral performance. On The first day of ticket sales, the school sold 10 adult tickets and 10 child tickets for a total of $200. On the second day, the school sold 13 adult tickets And 2 child tickets for a total of $172. How much did each child ticket cost? \n" ); document.write( "

Algebra.Com's Answer #763900 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "With basic algebra....

\n" ); document.write( "10a+10c = 200
\n" ); document.write( "13a+2c = 172

\n" ); document.write( "Solve by any method you like. Note that the first equation is equivalent to a+c = 20; whatever solution method you use, that will make things easier.

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\n" ); document.write( "The same thing, doing mostly the same calculations as with algebra, but informally, using logical reasoning instead.

\n" ); document.write( "(1) 10 adults plus 10 children equals $200, so 2 adults plus 2 children equals $200/5 = $40.
\n" ); document.write( "(2) Compare that to 13 adults plus 2 children equals $172; the difference is 11 adults for $132.
\n" ); document.write( "So each adult ticket costs $132/11 = $12; then each child ticket costs $8. \n" ); document.write( "

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