document.write( "Question 1143096: The length of a rectangle is 2 more than 5 times its width. Find the area of the rectangle if its perimeter is 64 in. \n" ); document.write( "
Algebra.Com's Answer #763868 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! let l be the length of the rectange and w be the width of the rectangle \n" ); document.write( ": \n" ); document.write( "l = 5w +2 \n" ); document.write( ": \n" ); document.write( "2l +2w = 64 \n" ); document.write( ": \n" ); document.write( "2 * (5w+2) + 2w = 64 \n" ); document.write( ": \n" ); document.write( "10w +4 +2w = 64 \n" ); document.write( ": \n" ); document.write( "12w = 60 \n" ); document.write( ": \n" ); document.write( "w = 5 \n" ); document.write( ": \n" ); document.write( "l = 5 * 5 +2 = 27 \n" ); document.write( ": \n" ); document.write( "Area of rectangle = 27 * 5 = 135 square inches \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( " |